A Bag Of Marbles Contains 120 Red And Yellow Marbles

Let x number of red marbles.

A bag of marbles contains 120 red and yellow marbles.

The probability of consecutively choosing two red marbles and a green marble without replacement. A handful of 5 marbles is grabbed from the bag. The probability of choosing first red marble is 5 12 because there is not any replacement now 4 red marbles are remained and totally 11 marbles. If lisa draws a random marble from the bag what is the probability that it will be a red green or blue marble.

Asked by lyla on april 18 2014. 2 put value of x in 1 we get put y 6 in 2 we get hence there are 114 red marbles in the bag. Learn more. Y number of black marbles.

Asked 03 10 20 a bag contains yellow marbles and red marbles 16 in total. A random variable assigns the number of red marbles to each outcome. 1 there are 19 red marbles every for black marble. Which can be re expressed as.

A bag contains nine red marbles four green marbles three blue marbles and two yellow marbles. A bag contains 4 yellow 2 red and 6 green marbles. The number of different handfuls of 5 marbles with exactly 2 green and no yellow marbles is. There are 114 red marbles in the bag.

Calculate the expected value of the random variable. The number of yellow marbles is 1 more than 2 times the number of red marbles. A bag contains 120 marbles. The ratio between blue and red marbles is therefore.

Thus the probability of choosing the second red marble is 4 11. A bag contains 70. P 3 10 7 9 2 8 p 7 120 since we were ask to find the probability of chosing 1 red 1 black and 1red marble without replacement after each draw we can use the fundamental method in finding the probability. By dividing both sides by the common factor 40.

If there are only red and blue marbles and out of the 120 in total there are 80 blue marbles then there must be 120 80 40 red marbles. Two marbles are drawn. A bag contains 9 red marbles 8 white marbles and 6 blue marbles.